How to install ACC triangle miner

1. This is not very clear. The assembly and proction of mining machines are generally in the Pearl River Delta region, with Shenzhen and Dongguan as the majority
the maintenance of bitcoin mining machines is generally not too difficult. If there are many machines, it is better to return to the factory for maintenance
nowadays, most of the new coins do not need to be mined. For example, Ruitai coins are mined at one time.

2. Triangle miner bought one, not very feeling, I'm going to buy another star bit hummingbird H1

3. 过E作EG∥BC交AD于G,
则EG/CD=AE/AC=3/4,∴CD=4/3EG,
∵BF=EF,∴EG/BD=EF/BD=1,∴EG=BD,
∴BD：DC=EG：4/3EG=3：4.

4. Try not to do it. These two cars do not have the original system. ACC is not just radar + throttle control

5. You should be talking about ACG's

it's specially designed for outdoor by Nike

it links a
all conditions gear, which means all day adaptation series, mainly for outdoor series. I like it very much. I only like ACG's in all things of Nike. I think it's super good, but the price is generally higher than other series, In summer, ACG clothes are usually made of quick drying fabrics, while in winter, ACG clothes are mainly made of down jacket and cotton jacket, which are generally more than 1000. It's more casual, and it's not the kind of Nike sports style. Of course, the most famous ACG clothing is its assault suit, which is resistant to rain and snow. The fabric is very strong. It's hard to get dirty, and the rain can't get through, There are also high-end emergency avalanche rescue system (mainly used to keep body temperature from losing) and snow proof glasses (usually kept in windproof hat), but the price is basically more than 2500 (although I like it very much, I always feel that the cost performance ratio is not very high, so I haven't bought an ACG assault suit up to now, which costs a lot of money),

6. (1) It is proved that: ∵ AB = AC, ∵ B = ACB. And ∵ quadrilateral ABDE is parallelogram, ∵ AE ∥ BD, AE = BD. ∴∠ACB=∠CAE=∠B In △ DBA and △ AEC, ∵, ≌ △ DBA ≌ △ AEC (SAS) 2) AG ⊥ BC is made through a, and G is the foot drop. Let Ag = x, and in RT △ AGD, ∵ ADC = 45 °， ∴AG=DG=x In RT △ AGB, ∵∠ B = 30 °， ∴ And ∵ BD = 10, ∵ bg-dg = BD, that is, the solution is obtained. ∴

7. Let BP = x, then PC = 10-x, from PE parallel to AC, we can get EBP ∽ ABC, s EBP: s ABC = (x / 10) ^ 2, s EBP = (x ^ 2 / 100) s ABC; Similarly, s FPC = (10-x) ^ 2 / 100 · s ABC, so s parallelogram aepf = s ABC - (x ^ 2 / 100) s ABC - (10-x) ^ 2 / 100 · s ABC is reced to s parallelogram aepf = - s ABC / 50 (X-5 ^ 2 + s ABC / 2). When x = 5, that is, point P is the midpoint of BC, the area of parallelogram is the largest, half of triangle area

8. ACG, right? Nike outdoor procts

9. It is proved that: ∵ ad · AB = AE · AC
AE / AB = ad / AC (the basic property of proportion)
and ∵ a = a
and ∵ Abe ∽ ADC