Supm digital currency price
Publish: 2021-05-19 02:16:26
1.
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information network is the basis of the development and utilization of information resources and the application of information technology, and is a necessary means of information transmission, exchange and sharing
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only by building an advanced information network can the overall benefits of informatization be brought into full play. Information network is an important infrastructure of a modern country
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information network not only meets the transmission and communication functions required by information technology application and information resource distribution processing, but also puts forward requirements for the other three elements
2. 1200kg / m3
1200kg / m3
that "sup" means index, and the following 3 is index, which is 3
density unit.
1200kg / m3
that "sup" means index, and the following 3 is index, which is 3
density unit.
3. The middle R represents the radius of the ball
when the object moves near the surface of the ball, the radius from the center of the ball to the object should be calculated
when the satellite moves, the distance between the object and the surface of the ball should be calculated
the velocity of circular motion around the surface of the ball expressed by these formulas
for example: v = (GM) ÷ r½
linear velocity = root (mass of central celestial body) × Gravitational constant ÷ Radius of the ball)
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when the object moves near the surface of the ball, the radius from the center of the ball to the object should be calculated
when the satellite moves, the distance between the object and the surface of the ball should be calculated
the velocity of circular motion around the surface of the ball expressed by these formulas
for example: v = (GM) ÷ r½
linear velocity = root (mass of central celestial body) × Gravitational constant ÷ Radius of the ball)
you're welcome
4. 1) equals 65372;m-1, m-3*;-5-m, ++-m-6 ÷ m-1-3m+15+m-6=-m+8
2)2 (x ²); y++12308; ²+ 2(y+2x)(y+2x)-(y+2x) y-x
=2x² 2y-x²+ 2y+4x-x. y+x
=5x-y
=4x+y+x-2y
=5+(-3)
=2
2)2 (x ²); y++12308; ²+ 2(y+2x)(y+2x)-(y+2x) y-x
=2x² 2y-x²+ 2y+4x-x. y+x
=5x-y
=4x+y+x-2y
=5+(-3)
=2
5. BC/AB=tanA=√2/4
∴BC=√2/2即b²/a=√2/2
∵c=1∴解得a=√2 b=1
∴椭圆方程为x²/2 - y² =1
当直线的斜率不存在时,MB=NB=3/√2 ,MN=√2
∴∠MBN为锐角.不满足
当直线的斜率存在时.设直线方程为y=k(x+1)
与椭圆方程联立得1-2k²)x²-4k²x-2k²-2=0 ①
δ＞0得k²＜1
设M(x1,y1) N(x2,y2)
∴向量BM=x1-1,y1) 向量BN=x2-1,y2)
∵∠MBN为钝角∴向量BM·向量BN＜0
即(x1-1)(x2-1)+y1y2＜0
∴(1+k²)x1x2+(k²-1)(x1+x2)+k²+1＜0 ②
由①知x1x2=(-2k²-2)/1-2k²) x1+x2=4k²/1-2k²)
代入②得2k的四次方+7k²+1)/(2k²-1)＜0
∴2k²-1＜0
∴k²＜1/2
∴-√2/2＜k＜√2/2
∴BC=√2/2即b²/a=√2/2
∵c=1∴解得a=√2 b=1
∴椭圆方程为x²/2 - y² =1
当直线的斜率不存在时,MB=NB=3/√2 ,MN=√2
∴∠MBN为锐角.不满足
当直线的斜率存在时.设直线方程为y=k(x+1)
与椭圆方程联立得1-2k²)x²-4k²x-2k²-2=0 ①
δ＞0得k²＜1
设M(x1,y1) N(x2,y2)
∴向量BM=x1-1,y1) 向量BN=x2-1,y2)
∵∠MBN为钝角∴向量BM·向量BN＜0
即(x1-1)(x2-1)+y1y2＜0
∴(1+k²)x1x2+(k²-1)(x1+x2)+k²+1＜0 ②
由①知x1x2=(-2k²-2)/1-2k²) x1+x2=4k²/1-2k²)
代入②得2k的四次方+7k²+1)/(2k²-1)＜0
∴2k²-1＜0
∴k²＜1/2
∴-√2/2＜k＜√2/2
6. It's the kilogram divided by three meters, which is a unit of moment of inertia
7. m+n)⁴×(n-m) ²×(m-n)+(n-m) ³×(n+m) ²×(m+n) ²
=m+n)⁴×(m-n) ²×(m-n)-(m-n) ³×(m+n) ²×(m+n) ²
=m+n)⁴×(m-n) ³-(m-n) ³×(m+n)⁴
=0
=m+n)⁴×(m-n) ²×(m-n)-(m-n) ³×(m+n) ²×(m+n) ²
=m+n)⁴×(m-n) ³-(m-n) ³×(m+n)⁴
=0
8. m²-n²
9. It means cube
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