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How to calculate the axial force of frame under constant load

Publish: 2021-05-25 06:08:16
1.

The axial force of AC section is - 20KN, not - 10kN. Because - 10kN acts on point C, the AC is disconnected, the left part is taken as the isolator, and only the left end bears the axial force of - 20KN, so the axial force is - 20KN. Similarly, the axial force of CD segment is - 10kN, and that of de segment is + 10kN

For columns with large slenderness ratio, the initial eccentricity caused by various accidental factors cannot be ignored. With the increase of the load, the lateral deflection also increases. The compression deformation and bending deformation of the member occur at the same time. Finally, the member is destroyed under the combined action of axial pressure and additional bending moment

firstly, the concavity compressive concrete is crushed, the longitudinal reinforcement is bent and bulged out, and the concrete cover is peeled off; At the same time, when the convex surface is under tension, the concrete will proce horizontal cracks, the lateral deflection will increase sharply, and the column will be damaged

Extended data:

for short columns with longitudinal bars and stirrups, the strain of the whole section is basically uniform under axial load. When the load is small, the concrete and steel are in the elastic stage. As the load continues to increase, the lateral deformation of the concrete increases, the fiber stress at the edge of the section first reaches the tensile strength of the concrete, and micro cracks begin to appear in the column

After

because the elastic molus of steel bar is greater than that of concrete, the stress of steel bar increases rapidly, the stress of column longitudinal bar first reaches the tensile strength of steel bar and is crushed, and micro cracks begin to appear in the column

2. The axial force at the bottom of the column is the axial force at the top of the column plus the self weight of the column itself, which is only considered when calculating the vertical dead load. When calculating the live load, the axial force at the top and bottom of the column take the same value.
3. The axial force at the upper end of each column is obtained by adding the shear force at the end of the transverse frame beam, the reaction force at the end of the longitudinal frame beam (calculated according to the simply supported beam) and the axial force from the upper column; The axial force at the lower end of each column is the axial force at the upper end plus the self weight of the column

vertical load is the gravity of various structural members and attachments perpendicular to the ground.
4. Force transfer process: the plate is transferred to the secondary beam, the secondary beam is transferred to the main beam, and the main beam is transferred to the column
the short side of two-way slab is triangle, the long side is trapezoid, and the one-way slab is transferred according to the long side. After drawing the force transfer of slab, the analysis shows that if the concentrated load = slab weight, longitudinal wall weight (decting window weight), window weight and longitudinal beam weight. Hope to help you.
5. Under pressure and torsion
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7. There is no 7.6 in the axis
set the concentrated wind load on the top floor as h, H × Top floor height ÷ AC=2.9 Here AC is the distance between a and C.
8. I usually send integrated package
9.

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