How to calculate the applied axial force

1.

1. The calculation of the circumferential force of the belt pulley

first use the conversion ratio of the belt pulley speed and the belt pulley diameter, speed ratio = output speed: input speed = pitch circle diameter of the load belt pulley: pitch circle diameter of the motor belt pulley. The circular force and the reference force are the same, diameter - 2H = pitch circle diameter, h is the groove depth on the reference line, different types of V-belt h are different, yzab CDE, the circular force on the reference line are h = 1.62 2.753.54.88.19.6 respectively

2. Calculation of belt pulley radial force:

the radial force is the theoretical force of belt pulley pitch line position, which is generally expressed by PD, and the outer circle is generally expressed by OD. The conversion formula of pitch circle and outer circle is different for different groove types. Generally, it is easy to measure the outer circle of pulley, and calculate pitch circle according to the formula. SPZ:OD=PD+4; SPA:OD=PD+5.5; SPB:OD=PD+7; SPC:OD=PD+9.6

The axial force of the pulley is set as D1, N1 for the diameter and speed of the motor pulley (driving pulley) and D2, N2 for the diameter and speed of the driven pulley; That is, D2 = D1 * (N1 / N2). The minimum outer diameter of pulley a or spa is 80mm, SPZ belt, and the small pulley is not less than 63mm

extended data:

the recommended degree of pulley groove angle for different types of pulleys in different diameter ranges

1. The recommended degree of pulley groove angle for O-type pulleys is 34 degrees when the pulley diameter ranges from 50 mm to 71 mm; 36 degrees in the range of 71mm to 90mm, & gt; It is 38 degrees at 90mm

2. The diameter of A-type pulley is 34 degrees when the pulley diameter ranges from 71mm to 100mm, and 36 degrees when the pulley diameter ranges from 100mm to 125mm& gt; 38 degrees at 125 mm; When the diameter of B-type pulley ranges from 125mm to 160mm, it is 34 degrees; 36 degrees at 160 MM-200 mm, & gt; When 200 mm, it is 38 degrees

3. C-type pulley is 34 degrees when the pulley diameter ranges from 200 mm to 250 mm and 36 degrees when the pulley diameter ranges from 250 mm to 315 mm; 38 degrees at 315 mm

When the diameter of D-type pulley is 355mm-450mm, it is 36 degrees; At 450 mm, it is 38 degrees; E type is 36 degrees from 500mm to 630mm; It is 38 degrees when 630mm

2. For example, when you transfer money to me, I will give you a string of codes. This code is the address where I collect money. The address format corresponding to different currencies will be different, so we must repeatedly confirm whether the address is the currency in the transfer operation. For example, if you use the address of bitcoin to transfer money to the address of Ethereum, it will judge that it is not the address of bitcoin and refuse. However, if you insist on doing so, it may cause the loss of assets. So the address must be verified repeatedly before transfer. You should also pay special attention to whether the first few and the last few are exactly the same as the address given to you by the other party< When it comes to this address, it actually has another function. Blockchain is a completely transparent network. When you give someone an address, it is possible for others to query the transfer, flow and balance of your address. So when we use the address, we should also pay attention to personal privacy. For example, if you give address a to someone, you'd better give address B to another person. This is the most convenient way to protect your privacy.

3. If only the axial force inside the bearing is considered, there are: FA1 & gt; Fa2

please accept, thank you!

4. To find the center of mass of the rotating body (that is, the center of gravity), and measure the distance r from the center of mass to the axis, the rotational speed w (angular velocity), and the mass m, then the force is f = MRW * W.

5. The theory of deep groove ball bearing does not derive axial force, but it will be subject to slight axial force in the process of practical application, because it has a certain centering effect. After the axial force disappears, it will return to the original position
the size of the axial force should be related to the actual working environment. After the axial force is applied, the force of the ball bearing is equivalent to having a contact angle, which is similar to the angular contact ball bearing. The axial force also has a great relationship with the clearance and radius of the bearing itself
especially the clearance, the larger the clearance is, the larger the range of motion of the ball in the axial position is, that is, the larger the axial clearance is, the greater the axial force it can bear, but the clearance can not be blindly large
in a word, I can tell you that the axial force is far less than the radial force. As for the specific calculation, because the contact angle is unpredictable, there is no way to know
the selection of deep groove ball bearing is unreasonable if the bearing is subjected to radial load and continuous axial load at the same time, because continuous axial force will rece the service life of deep groove ball bearing. Angular contact ball bearing or tapered roller bearing can be selected according to rotating speed and other instries and mines, and four point contact ball bearing can also be selected if bidirectional axial force is required, Double row tapered roller bearing or double row angular contact ball bearing.

6.

1、 The necessary condition for cutting tool to cut into rock is p < sub > y < / sub > ≥ s < sub > 0 < / sub > 0· σ Where: P < sub > y < / sub > is the axial pressure on a cutting tool; S < sub > 0 < / sub > is the contact area between cutting tool and rock; σ Is the critical compressive strength of rock

Fig. 1-3-8 force system balance diagram of cutting tool when cutting into rock γ It moves downward in the direction of; γ The angle depends on the friction coefficient of rock to metal and the cutting edge angle of the cutting tool β Therefore, on the front ob, positive pressure n < sub > 2 < / sub > and frictional resistance n < sub > 2 < / sub > Tan are generated ring the cutting process φ tan φ Equal to the friction coefficient f). Similarly, positive pressure n < sub > 1 < / sub > and frictional resistance n < sub > 1 < / sub > Tan are proced on the back slope φ， See figure 1-3-8

The balance relationship of each force is as follows:

rock breaking engineering

after simplification:

rock breaking engineering

∑ f < sub > y < / sub > = 0

rock breaking engineering

after simplification:

rock breaking engineering

substitute formula (1-3-2) into formula (1-3-3), According to the conditions of cutting tool cutting into rock:

rock breaking engineering

where: B is the width of cutting tool; B is the width of cutting tool; C is the width of cutting tool; C is the width of cutting tool; σ< Sub > n < / sub > is the normal pressure (or stress) on the surface; σ Is the pressure perpendicular to ab plane, equal to the compressive strength of rock

by substituting equation (1-3-5) into equation (1-3-4), the calculation formula of axial force is obtained as follows:

rock breaking engineering

after mathematical arrangement of equation (1-3-6), the cut in depth h < sub > 0 < / sub > should be:

rock breaking engineering

cos < sup > 2 < / sup > in the right bracket of equation (1-3-7) φ/ sin β+ two φ= Z. There are:

rock breaking engineering

where Z is the cutting edge angle β And the friction angle between cutting tool and rock φ In general, z = 0.88-0.97

The

formula (1-3-8) is basically confirmed for plastic rocks. That is to say, the cutting depth is basically proportional to the axial pressure P < sub > y < / sub >, but not to the cutting tool width B and the cutting edge angle β And the compressive strength of rock. For brittle rocks, the breaking depth is greater than the cutting depth

(2) calculation of horizontal force when large shear occurs in rock e to horizontal force, the cutting tool must approximately overcome the shear resistance of rock mass with area CC ′ B ′ B and side area ABC and a ′ B ′ C ′ in Fig. 1-3-9 and the friction between the cutting tool and groove bottom

Figure 1-3-9 the resistance of the cutting tool in large shear is as follows: the area of CC ′ B ′ B is equal to, and the side area of ABC and a ′ B ′ C is equal to

When

shear aa'bb'cc ', the shear resistance is equal to:

rock breaking engineering

where: σ< Sub > 0 < / sub > is the shear strength of rock

When shearing AA ′ BB ′ CC ′ rock mass, the total resistance to be overcome is equal to:

rock breaking engineering

where f < sub > 1 < / sub > is the internal friction coefficient of rock

If equation (1-3-9) and equation (1-3-10) are equal, the relationship between P < sub > x < / sub > and P < sub > y < / sub > can be obtained:

rock breaking engineering

according to the formula (1-3-11), P < sub > x < / sub > force is related to B, h,

x < / sub > force σ< Sub > 0 < / sub >, P < sub > y < / sub >, F, and COS β In inverse proportion

7. According to the cutting parameters and spindle speed into the formula can be calculated

8. See which direction of the resultant force is larger, the bearing axial load in the larger direction is the largest resultant force, and the axial force of the other bearing is equal to its derived axial force.

9. I think the vertical use of the external axial force is like a rotating pressure in the heart.