Ethernet computing power of 370 graphics card

1. It's better not to exceed 1100 cores. In fact, 1050 cores are just a little bit more than 1100 cores. Because even if you go up, it won't be obvious. The card game is still the card. Don't exceed the video memory. The core performance of 370 is only average at present. Bandwidth is not the bottleneck. In fact, it's just a little bit more psychological comfort

2. The lack of power supply may be one reason, but your CPU may not be as good as others.

3. There are two kinds of 2G and 4G
2G is enough
the price is more than 800-900, buy more than 800, even if the cost-effective
this card performance is slightly better than gtx950, power consumption is about 110-120w.

4. The gold pick accelerates the digging speed, but its rability is very small, so it can only dig ordinary stones. The iron pick is used for digging, the gold draft is used to increase the digging speed, and the diamond draft is used to increase the rability

5. In consideration of the same synchronous and continuous related system, if the object keeps moving around the fulcrum, If the acceleration vector of the center of gravity of the system object is a (the vector sum of rotation acceleration and centripetal acceleration)
then f-joint = am

any force can be reflected in the center of gravity
f-joint = f-joint + f-joint
so f-joint = am-f-joint

for example:
there is an experimental mechanism in the automotive design center, which is a group of transmission intermediate gear shafts, There are three gears and a cam in the middle gear shaft which are under unbalanced force ring the test experiment. Gear 1 (with meshing radius of R1) is used to receive the drive. For example, the change gear system is subject to the downward meshing force of the left clutch drive gear F1
gear 2 (with meshing radius of R2) is used to transmit the main load, For example, the automobile load worm synchronous gear
receives the downward meshing force F2 of the right load gear
the gear 3 (meshing radius is R3) is transferred to the secondary load, for example, the small generator spindle gear
receives the rightward meshing force F3 of the upper meshing gear
the cam (eccentricity is R4) is used for revolution detection and hydraulic force supply, and receives the constant left spring force F4 (F4), It is known that the mass of the whole wheel group is m, and the average radius of inertia is r
where the total mass of the gear and shaft is M1, the eccentric wheel is M4, and M = M1 + M4
at a certain stage, the angular acceleration of the gear shaft is j in the process of accelerating rotation, and it reaches the maximum value at a certain moment ω Angular velocity, the highest part of the cam faces to the right
solution: at this moment, the fulcrum of the gear shaft is forced, (ignoring the bearing friction)
note: (it is not necessary to pass the gravity and the bearing support force, In other words, the supporting force overcomes the gravity and forms the fulcrum compound force)

1: according to my method,
the eccentric distance of the whole center of gravity = M4 * R4 / M = R4 * M4 / m, the cam orientation is the instantaneous eccentric orientation (horizontal right)
let it be expressed by R below, r = R4 * M4 / M
in addition, according to the driving force analysis, The rotation direction of the system is anticlockwise, so the center of gravity is doing upward acceleration J
and left centripetal acceleration X= ωω R
then the sum of global acceleration vector = √ (JJ + XX) = √ (JJ + XX)+ ωωωω RR)
so f = am = m √ (JJ)+ ωωωω RR)
other forces except fulcrum
have downward F1 + F2
rightward f3-f4
when vector representation is used, f branch = fhe-f1-f2-f3-f4 (all with transverse vector representation)
the operation process must be all transformed into complex trigonometric function representation, which is somewhat complicated
in order to simplify, we divide it into horizontal and plumb direction (horizontal to right is positive, horizontal to right is positive, horizontal to right is positive, horizontal to right is positive, horizontal to right is positive, horizontal to right is positive, horizontal to right is positive, horizontal to right is positive, The vertical component of F is + MJ, the horizontal component is - MX, the vertical component is - F1, the vertical component is - F2, the horizontal component is F3, the horizontal component is - F4, The same below)
vertical component of f-branch = MJ + F1 + F2

f-branch vector = √ (f-branch horizontal ^ 2 + f-branch vertical ^ 2) direction = arctan (f-branch vertical / f-branch horizontal)

2: combined with moment calculation (take the value as an example)
If M1 = 8kg M4 = 2kg M = M1 + M4 = 10kg r = 0.25 R4 = 0.04m
R1 = 0.2m R2 = 0.4 R3 = 0.6
F1 = 1000N F2 = 400N F3 = 50N F4 = 100N
then F1 moment is 1000 * 0.2 = 200N
F 2 torque is 400 * 0.4 = 160nm
F3 torque is 50 * 0.6 = 30nm
F4 without torque, the rotation torque is 200-160-30 = 10nm
J = 10nm / M / r = 10 / 10 / 0.25 = 4radians / s
If acceleration is 2.5 seconds to ω= Because r = r4m4 / M = 0.04 * 2 / 8 = 0.01M
x= ωω R = 1 m / s, s
then f-joint horizontal = - MX = - 10 * 1 = - 10N, f-joint vertical = + MJ = 10 * 4 = 40n
then f-branch horizontal = f4-mx-f3 = 100-10-50 = 40n (positive value indicates right direction)
f-branch vertical = MJ + F1 + F2 = 40 + 1000 + 400 = 1440n (positive direction upward)
the force on f-branch is slightly right inclined upward

I hope you can understand it, just for example

6. The figure in the picture can't be seen clearly
if the center of gravity is O, the force on fulcrum A is: weight times (Bo divided by ab)

7.

Lever principle is also known as "lever balance condition". In order to balance the lever, the two torques (the proct of force and arm of force) acting on the lever must be equal. That is: power × Power arm = resistance × The resistance arm is expressed as F1 · L1 = F2 · L2. Where F1 is power, L1 is power arm, F2 is resistance and L2 is resistance arm

when using the lever, in order to save effort, the lever with the power arm longer than the resistance arm should be used; If you want to save distance, you should use a lever whose power arm is shorter than the resistance arm. Therefore, the use of leverage can save labor and distance. However, in order to save effort, we must move more distance; If you want to move less distance, you have to work harder

the fulcrum of the lever does not have to be in the middle. The system that satisfies the following three points is basically the lever: fulcrum, force application point and force bearing point

Based on the "center of gravity" theory, Archimedes discovered the lever principle, that is, "when two weights are balanced, their distance from the fulcrum is inversely proportional to their weight." Archimedes' research on leverage not only stays in theory, but also makes a series of inventions based on this principle

In the battle to protect Syracuse from the attack of the Roman Navy, Archimedes used the lever principle to make a long-distance and short-range catapult, and used it to shoot all kinds of missiles and boulders to attack the enemy, which blocked the Romans from outside Syracuse for three years

8. Situation setting:
a solid triangle fulcrum; An object weighs g and will be lifted as a source of resistance. The force application point is at one end of the rod. The length of a rod without mass is L. the force application point of a person is at the other end of the rod. As a power to lift an object, now we study where the fulcrum receives the maximum and minimum pressure on the rod< Research methods:
is the force balance
problem discussion:
1. In view of the size and direction of the force, it is necessary to decompose the force (power and resistance), synthesize the effective force to the fulcrum, and get the pressure on the fulcrum
2. The pressure of the pole on the fulcrum is its supporting force on the pole. The direction of the force is generally upward. With the prying of the pole, the direction of the supporting force is always perpendicular to the pole; In addition, there needs to be friction at the fulcrum
3. Therefore, with the lever prying, the pressure on the fulcrum will change, no matter where the fulcrum is
simplified mode:
keep the lever in a horizontal state, the direction of gravity a (resistance) and hand pressure B (power) of the object is vertical to the downward direction of the lever (the lever is horizontal), and the direction of the supporting force C (the pressure on the fulcrum) of the fulcrum to the lever is vertical to the upward direction of the lever, so there is no need to decompose and synthesize the force, Then a + B = C. now a is constant, and B changes with the fulcrum. Because it's vertical, friction doesn't have to be taken into account
conclusion:
the closer the fulcrum is to the object, the smaller the pressure on the fulcrum (because the labor-saving lever B is smaller),
the closer the fulcrum is to the power application point, the greater the pressure on the fulcrum (because the labor-saving lever B is larger),
when the fulcrum is in the middle of the rod, because a = B, the pressure on the fulcrum is twice the gravity of the object (because it is an equal arm lever)

remarks:
when the pole is not horizontal, the force analysis is relatively simple, but it is cumbersome and omitted.

9. The force on the fulcrum under lever balance is the sum of the forces on both sides of the lever. Suppose that both sides of a lever are subject to 5N and 10N forces respectively. Because of the lever arm, the force on the fulcrum is 15N, which has nothing to do with the length of the lever

10. The force on the fulcrum and the action line of the force pass through the fulcrum, so the arm of force is 0, which has no effect on the rotation of the lever, and does not need to be considered in the calculation