Calculation force of standard value of uniformly distributed var
Formula = 2500 * thickness, that is, the specific gravity of reinforced concrete is 2500 kg / m3, and the thickness of slab is equal to the uniformly distributed permanent load of slab
For example, if the thickness of the plate is 130, the uniformly distributed permanent load of the plate is 2500 * 0.13 = 325kg / m2 When1kg force = 9.8N, the common value is 10, then 325kg / m2 = 3.25kn/m2
In the finite element displacement method, the method of discretizing a plate into triangular elements with nodes at the corners has been denied, because it leads to the singularity of elements in a certain direction However, it is not suitable for non rectangular plates The key to the development of finite element displacement analysis of thin plate is the completeness and convergence of the element displacement mode and the deformation compatibility of the two span element. The element in sapv program conforms to the above properties, but the calculation workload is largeuniform load of beam = height of beam * weight of reinforced concrete 25kn / m3
M1 = QL & # 178; ÷ 8=1.2 × 10+1.4 × 8 × 7² ÷ 8 = 142.1kn · m
bending moment proced by concentrated force:
M2 = pl ÷ 4=(1.4 × 5 × seven ÷ 4=12.25KN·M
M=M1+M2=142.1+12.25=154.35KN·M
basic combination calculation for permanent load control 1.35 × 25.5+1.4 × ten point nine × one × 0.7+1.4 × eight point five × one × 0.6 = 52.25
basic combination calculation under variable load control 1.2 × 25.5+1.4 × ten point nine × 1.0+1.4 × one × eight point five × 6 = 53
therefore, the basic combination value of bearing capacity should be 53kn / m.
There are many flaws in this topic, which is difficult for examinees and wrong for children! It's pathetic
According to the precondition, the combination of load effect can be basic combination or standard combination. Is the required answer the design value of basic combination or standard combinationthe partial factor of load is not given, so it is necessary to calculate whether the partial factor of permanent load should be 1.35 or 1.2 in the basic combination, but the question is not clear whether it is the basic combination
the questions are two small questions (variable load is different), but there is only one group of answers! How to choose and answer
the standard term is the coefficient of combination value ψ c. Quasi permanent coefficient ψ q. The title is not a standard word
as a teaching concept, it should be rigorous, and closely follow the code of GB 5009-2012< br />
the controllable live load refers to those loads that will not change significantly with time, such as the uniform live load on the floor of the library, storage room, computer room, parking garage, and instrial floor
load, pronunciation: H è z à i“ "Zai" has the meaning of "bearing", so "Nian Si Sheng" refers to the external forces and other factors that cause internal forces and deformation of the structure or components. Generally speaking, it refers to all kinds of direct actions exerted on the engineering structure to make the engineering structure or components proce effects. The common ones are: structural dead weight, floor live load, roof live load, roof ash load, vehicle load, crane load, equipment dynamic load, wind, snow, ice, wave and other natural loads
live load is short for live load, also known as variable load, which is imposed on the structure by people, materials and vehicles caused by the use or occupation load and natural load. Such as instrial building floor live load, civil building floor live load, roof live load, roof ash load, vehicle load, crane load, wind load, snow load, ice load, wave load, etc
The design value of the load is equal to the standard value of the load multiplied by the partial factor of the load
examples of live load: such as instrial building floor live load, civil building floor live load, roof live load, roof ash load, vehicle load, crane load, wind load, snow load, ice load, wave load, etc
reference value of common live load:
1. Standard value of equivalent uniform load of fire engine: 20KN / m2
Roof Garden: 3kn / m2 3. Accessible roof: 2Kn / m24. Construction live load of podium level: 4kn / m2
5. Elevator room: 7kn / m2
extended data
load type:
1, photoelectric infrared load
one of the advantages of Tactical UAV is that it can be close to the target to carry out reconnaissance, and small aircraft can even fly over the target and shoot at a distance of 100 ~ 200m. With the development of photoelectric technology, the weight, volume and cost of TV cameras and infrared thermal imagers are greatly reced. These reconnaissance equipment have been loaded on small or even micro UAVs
Synthetic aperture radar (SAR) can work effectively at night and in bad weather. It can penetrate through clouds, fog and battlefield cover, and image in a large range with high resolution. With the development of light antenna and compact signal processing device and the rection of cost, SAR has been able to be equipped on Tactical UAV The wavelength of lidar is short, it can not only detect the targets under the cluster leaves, but also classify the targets, and provide the accurate target information for the ground forces
concentrated line load = permanent load (dead weight of reinforced concrete) × Partial factor + Construction uniform live load × Partial coefficient
self weight of reinforced concrete = sectional area of beam (m * m) × 25kn / m * m * m (25kn / m * m * m is the specific gravity of reinforced concrete, converted into kn / m * m * m as the unit, and the specific gravity of reinforced concrete is 25kn / m * m * m when calculating the concentrated line load.)
construction uniform live load = beam width m × 3kn / m * m
partial factor: the partial factor of permanent load is 1.2; The partial coefficient of uniformly distributed live load is 1.4
example: beam height 1600, beam width 400
1.2x1.6x0.40x25 + 1.4x0.40x3 = 20.88, greater than 20. It is necessary to carry out special expert argumentation
the total construction load is used to calculate the slab load, and the principle is the same as above
for example, the standard value of construction uniform load is 4kn / m2, which means that 400 kg of things can be placed per m2, such as stacking cement, sand, formwork, etc
I hope the answer will help you!